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 Exercise [07.05] 
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Joined: 12 Apr 2008, 11:02
Posts: 1
Post Exercise [07.05]
Hi everybody,

Fisrt of all, I would like to apologize for my sometimes poor english, but english is not my native language.

Here is a solution of exercise 7.5.

Regards,


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13 Apr 2008, 14:03
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Joined: 13 Mar 2008, 14:06
Posts: 39
Location: Ithaca NY
Post Re: Exercise [7.5]
Your argument about the second integral applies to any analytic function of course, not just e^{iz}., so all you need to be concerned about is what happens to arg(z) going around the little curve.
Now try it with the big semicircle in the lower half plane :)
Laura


14 Apr 2008, 17:10
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Joined: 30 Jun 2008, 22:14
Posts: 25
Post Re: Exercise [07.05]
This is a brilliant proof by Fred. The key here is Cauchy integral theorem, where the integral on a closed contour is zero. The bloody book didn't say anything about this theorem at all.

By substituting z with (r,\theta) the second and fourth integrals can be derived more quickly, without the need for integration by parts.


12 Jul 2008, 22:00
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Joined: 07 Jun 2008, 08:21
Posts: 182
Post Re: Exercise [07.05]
variounes wrote:
The bloody book didn't say anything about this theorem at all.


"This theorem" follows from Cauchy's formula which IS given in the book.


31 Dec 2008, 14:08
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Joined: 13 Aug 2009, 00:08
Posts: 13
Post Re: Exercise [07.05]
Well, Fred's solution starts by making use of the Residue theorem, which is given by exercise [7.4], and it also uses Cauchy's integral formula, which is given in section 7.3 of the book as vasco says.

Penrose didn't show that the integral around a contour is the sum of the integrals around contour segments, but he can only go so far, I guess.


17 Aug 2009, 07:38
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