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It is currently 04 Sep 2010, 13:02
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hans
Joined: 09 Jul 2008, 15:25 Posts: 2
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 Exercise [07.06]
For solution see wordfile
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| 09 Jul 2008, 15:28 |
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variounes
Joined: 30 Jun 2008, 22:14 Posts: 25
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 Re: Exercise [07.06]
This is brilliant, hans! I didn't know that poles and their orders can be found this way.
One question. In this solution, poles and their orders were first guessed, then proved. Does anybody know of a general procedure to arrive at these numbers without the guess work in the first place? Or is there any need for a general procedure at all?
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| 13 Jul 2008, 11:03 |
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hans
Joined: 09 Jul 2008, 15:25 Posts: 2
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 Re: Exercise [07.06]
To calculate the poles one has to calculate the zero’s of the denominator:
z^2.sin(az)=0 z=0 (2x) or sin(az)=0 z=0 2x) or az=kpi with k= ……,-3,-2,-1,0,1,2,3,…. z=0 (2x) or z= kpi/a z=0 (3x) or z= kpi/a with k=….,-3,-2,-1,1,2,3,….
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| 15 Jul 2008, 17:13 |
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